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A fruit basket contains 10 Guavas and 20 Bananas out of which 3 Guavas and 5 Bananas are defective. If two fruits selected at random, what is the probability that either both are Bananas or both are non-defective?
315/435
313/435
317/435
316/435
Answer & Explanation Answer – 316/435 Explanation : P(A) = 20C2 / 30C2, P(B) = 22C2 / 30C2 P(A∩B) = 15C2 / 30C2 P(A∪B) = P(A) + P(B) – P(A∩B) => (20C2/30C2)+(22C2/30C2)-(15C2/30C2)=316/435
By: Sandeep Dubey ProfileResourcesReport error
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