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A basket contains 5 black and 8 yellow balls. Four balls are drawn at random and not replaced. What is the probability that they are of different colours alternatively?
56/429
57/429
61/429
68/429
Answer – 56/429 Explanation : sol=> BYBY + YBYB = (5/13)*(8/12)*(4/11)*(7/10) + (8/13)*(5/12)*(7/11)*(4/10) = 56/429
By: Sandeep Dubey ProfileResourcesReport error
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