A train covers a distance of 3584 km in 2 days 8 hours If it covers 1440 km on the first day and 160...........

Quantitative Aptitude ( CCS) Problems on trains

A train covers a distance of 3584 km in 2 days 8 hours. If it covers 1440 km on the first day and 1608 km on second day. By how much does the average speed of the train for the remaining part of the journey differ from that for the entire journey?

3 km/h less

4 km/h more

3 km/h more

4 km/h less

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Explanation:

Average speed = Tatal DIstance traveled/Total time taken
Total time = 2 days + 8 hours = 56 hours
Average speed = 3584/56 = 64 km/hr
remaining part of journy = 3484 - (1440 + 1068) = 536 km
remaining time = 8 hours
Average speed of remaining part of journey = 536/8 = 67 km/hr
there fore 67 - 64 = 3 km/hr