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A man borrows 3000 rupees at 10% compound interest. At the end every year he pays rupees 1000 back. How much amount should he pay at the end of the fourth Year to clear all his debt?
Rs. 680.5
Rs. 651.3
Rs. 751.3
Rs. 790.3
After one year amount = 3000 *110/100 = 3300 He pays 1000 back, so remaining = 3300-1000 = 2300 After two year amount = 2300 *110/100 = 2530 He pays 1000 back, so remaining = 2530-1000 = 1530 After three year amount = 1530*110/100 = 1683 He pays 1000 back, so remaining = 1683-1000= 683 After fouth year = 683 * 110/100 = 751.3
By: Pranav Gupta ProfileResourcesReport error
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