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David invested certain amount in three different schemes A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme C was 150% of the amount invested in Scheme A and 240% of the amount invested in Scheme B, what was the amount invested in Scheme B?
Rs 5000
Rs 6500
Rs 8000
Rs 10000
Let x, y and z be the amounts invested in schemes A, B and C respectively. Then, add individual interest to get total using Si= pxrxt/100 [x x 10 x 1]/100 + [y x 12 x 1]/100 + [z x 15 x 1]/100 = 3200 10x + 12y + 15z = 320000…. (i)Now, z = 240% of y =(12/5)y……… (ii)And, z = 150% of x =(3/2)x so,x=(2/3 )z = (2/3) x value of z from ii x= (2/3) x (12/5) y = (8/5)y………..(iii) From (i), (ii) and (iii), we have : 16y + 12y + 36y = 320000 64y = 320000 y = 5000 Sum invested in Scheme B = Rs. 5000
By: Pranav Gupta ProfileResourcesReport error
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