Mixture 1 contains 20 of water and mixture 2 contains 35 of water 10 parts from 1st mixture and 4 pa...........

Quantitative Aptitude ( CCS) Percentage

Mixture 1 contains 20% of water and mixture 2 contains 35% of water. 10 parts from 1st mixture and 4 parts from 2nd mixture is taken and put in a glass. What is the percentage of water in the new mixture of glass?

17 (5/7)%

24 (2/7)%

28 (1/5)%

24 (1/7)%

छोटे Courses बड़े Results

Master Percentage

Prepare through Micro-courses

Try Now

Explanation:

Water in new mixture from 1st mixture = (20/100) * 10 = 2 parts
Water in new mixture from 2nd mixture = (35/100) * 4 = 7/5 parts
Required % =[ [2+ (7/5)]/(10+4)] * 100 = (17/70)*100 = 24(2/7)