Explanation:

- The word "ALLAHABAD" consists of 9 letters.

- The letters include: A (4 times), L (2 times), H (1 time), B (1 time), D (1 time).

- To find the total arrangements, use the formula for permutations of multiset:

$$

\frac{n!}{p_1! \times p_2! \times \ldots \times p_k!}

$$

- Here, n = 9 and the repeated letters are A (4!), L (2!).

- The calculation will be:

$$

\frac{9!}{4! \times 2!}

$$

- This simplifies to:

$$

\frac{362880}{24 \times 2} = 7560

$$

- Option 3: 7560 is the correct answer.