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If the ratio of the ages of two friends A and B is in the ratio 3 : 5 and that of B and C is 3 : 5 and the sum of their ages is 147, then how old is B?
27 years
75 years
45 years
49 years
- Start with the given ratios:
- The age ratio of A to B is 3:5. Let A = 3x and B = 5x.
- The age ratio of B to C is 3:5. Let B = 3y and C = 5y.
- Since B is common in both ratios, equate the two equations for B:
- 5x = 3y, solving gives x = (3/5)y.
- Substitute x in A's equation:
- A = 3*(3/5)y = (9/5)y.
- Use the total sum:
- A + B + C = 147.
- (9/5)y + 3y + 5y = 147.
- Convert to a single variable:
- (9/5)y + 8y = 147.
- ((9 + 40)/5)y = 147.
- 49y/5 = 147.
- Solve for y:
- y = 147 * (5/49).
- y = 15.
- Calculate B’s age:
- B = 3y = 3 * 15 = 45.
- ? B is 45 years old.
- Correct Answer: Option 3 – 45 years.
“”
By: sunny bhonsle ProfileResourcesReport error
Simranjit kaur
Here correct answer is 45years 3*15=45 27=3*9 is a's age not of the b
Yes, Kindly recheck . Option C is the right answer .
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