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Two rabbits start running towards each other, one from A to B and another from B to A. They cross each other after one hour and the first rabbit reaches B, 5/6 hour before the second rabbit reaches A. If the distance between A and B is 50 km. what is the speed of the slower rabbit?
20 kmph
10 kmph
15 kmph
25 kmph
Let second rabbit takes x hr with speed s2 First rabbit takes x-5/6 hr with speed s2 Total distance = 50km S1 = 50/(x-(5/6)) S2= 50/x As they cross each other in 1hr… Total speed = s1 + s2 Now, T = D / S 50/(s1+s2) = 1 x = 5/2, 1/3 Put x= 5/2 in s2 –> 20km/hr
By: Sandeep Dubey ProfileResourcesReport error
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