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Ajay covers certain distance with his own speed but when he reduces his speed by 10kmph his time duration for the journey increases by 40 hours while if he increases his speed by 5 kmph from his original speed he takes 10 hours less than the original time taken. Find the distance covered by him.
1000 km
1200 km
1500 km
1800 km
x/(y – 10) – x/y = 40 x = 4y(y-10) —(i) x/y – x/(y + 5) = 10 x = 2y(y + 5) — (ii) From (i) and (ii) => y = 25; x = 1500
By: Sandeep Dubey ProfileResourcesReport error
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