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A truck travelled to a place Q from P, the first 50 km at 10 kmph faster than the usual speed, but it returned the same distance at 10 kmph slower than usual speed. If the total time taken by the truck is 12 hours, then how many hours will travel at the faster speed?
8 hours
6 hours
2 hours
3 hours
Total time taken, [50/(x-10)] + 50/(x +10)] = 12 hours. By solving the equation, we get x = 15 Time is taken by the truck at faster speed = 50/(15+10) = 2 hours.
By: Sandeep Dubey ProfileResourcesReport error
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