A car after travelling 100 km from point A meets with an accident and then proceeds at 3 4 of its or...........

Quantitative Aptitude ( CCS) Time & distance

A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?

60km/hr

80km/hr

100km/hr

120km/hr

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Explanation:

let distance between A and B be D km and real speed of the car be S km/hr
First time car takes 90 minutes more and second time car takes 75 minutes more than scheduled time.
So, T1 – T2 = 15/60 = 100
15/60 = [100/s + (D -100)/(3s/4)] – [160/s + (D – 160)/(3s/4)] Solve this D will be cancelled and S comes out to be 80km/hr