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Ashwin has to travel from one point to another point in a certain time. Travelling at a speed of 6kmph he reaches 40m late and travelling at a speed of 8kmph he reaches 12 m earlier.What is the distance between this two points ?
27km
18km
15km
21km
D/6 – 40/60 = d/8 +12/60 d/6 – d/8 = 12/60+40/60 (8-6)d/48 = 52/60 2d/48 = 52/60 D = 52*48/60*2 = 20.8 = 21km
By: Sandeep Dubey ProfileResourcesReport error
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