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P walks with a speed of 6 km/hr and after 5 hr of his start, Q starts running towards P at a speed of 8 km/hr. At what distance from start will Q catch P.
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In 5hrs, P will cover 30 km. Now, at some distance ‘x’. So P will cover X distance and Q will cover 30 + X. x/6 = (30+x)/8 x = 90. So distance from start after which Q will catch P = 90+30 =120km.
By: Sandeep Dubey ProfileResourcesReport error
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