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The number 6n2+ 6n for all natural numbers n , is always divisible by ?
6 only
6 and 12
12 only
18 only
Explanation: 6n2+ 6n = 6n(n + 1) This number is clearly divisible by 6 and 12, Let’s check If n = 1 The value of 6n(n + 1) = 12 divisible by 6 and 12 If n = 2 The value of 6n(n + 1) = 36 also divisible by 6 and 12
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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