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Three buckets have their volumes in the ratio 5: 3: 4. They are full of mixtures of milk and water. The mixtures contain milk and water in the ratio of (3: 2), (4: 1) and (5: 3) respectively. The contents of all these three buckets are poured into a fourth bucket. The ratio of milk and wafer in the fourth bucket is:
23:41
79:41
83:45
79:65
let the three buckets contain 3x, 4x and 5x litres of mixtures respectively. Milk in 1st mix. = (5x) (3/5) liters = 3x liters Water in 1st mix. = 5x-3x = 2x liters Milk in 2nd mix. = (3x) (4/5) liters = 12x/5 liters Water in 2nd mix. = (3x – 12x/5) liters = 3x/5 liters Milk in 3rd mix. = (4x) (5/8) liters = 5x/2 liters Water in 3rd mix. = (4x – 5x/2)liters = 3x/2 litres Total milk in final mix. = (3x)+ (12x/5)+(5x/2) = 79x/10 liters Total water in final mix. = (2x) + (3x/5) + (3x/2) = 41x/10 Required ratio of milk and water = = 79 : 41.
By: Rishu Sondhi ProfileResourcesReport error
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