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The three perpendicular distance of three sides of an equilateral triangle from a point which lies inside that triangle are 6 cm, 9 cm, and 12 cm, respectively. The perimeter of the triangle is
42√2 cm
45√3 cm
52√2 cm
54√3 cm
let O be the point inside the equilateral triangle ABC of side ‘a’ cm. Let OR = 12 cm , OQ = 9 cm and AR = 6 cm Then, Area of triangle ABC = Area of triangle BOC + Area of triangle AOC + Area of triangle AOB √3/4 a^2= 1/2 BC×OR+1/2 AC ×OQ+1/2 AB× OP √3/4 a^2 = 1/2× a × 12 + 1/2×a ×9+1/2×a× 6 √3/4 a^2 = a (12/2+ 9/2+ 6/2) √3/4 a = ((12+9+6)/2) a = 4/√3 × 27/2 a = 54/√3 cm ∴ Perimeter = 3 × a = 3 × 54/√3 = 54√3 cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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