The difference between two parallel sides of a trapezium is 8 cm The perpendicular distance be...........

Quantitative Aptitude ( CCS) Mensuration 2D

The difference between two parallel sides of a trapezium is 8 cm. The perpendicular distance between them is 38 cm. if the area of the trapezium is 950 cm², find the length of the parallel sides.

30 and 40 cm

26 and 28 cm

29 and 21 cm

24 and 22 cm

छोटे Courses बड़े Results

Master Mensuration 2D

Prepare through Micro-courses

Try Now

Explanation:

Let the two parallel sides be a and b.
We know, Area = 1/2 × (sum of parallel sides) × height
According to the question,
a – b = 8
and 1/2 (a + b) × 38 = 950
⇒ a + b = 1900/38 = 50
From Eqs. (i) and (ii), we get
2a = 58
∴ a = 58/2 = 29 cm
Now, from Eq. (i),
a – b = 8
∴ b = a – 8 = 29 – 8 = 21 cm
∴ a = 29 cm, b= 21 cm