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There are three rows with three seats in each row. Four boys and two girls are to be seated in these three rows such that girls always sit in the last row. In how many ways the students can be seated?
3490
5040
2880
4560
None of these
Total students = 6, 4 boys and 2 girls.
There will be two cases
Students sitting in last row
Ways to seat girls
Ways to seat boys
Case I: Only two girls
3 × 2
6C4 × 4!
Case II: Two girls and 1 boy
3!
6C3 × 3!
Case I: only two girls in last row, number of ways to seat two girls on three seats = 3 × 2 Now, 4 boys are to be seated on 4 seats out of six seats Number of ways = 6C4 × 4!
Total ways = 3 × 2 × 6C4 × 4! = 2160
Case II: Two girls and one boy in last row, number of ways to select one boy out of 4 = 4C1
Number of ways to arrange two girls and one boy in last row = 3! Now, 3 boys are to be seated on 3 seats out of 6 seats
Number of ways = 6C3 × 3!
Total ways = 4C1 × 3! × 6C3 × 3! = 2880
Total ways = (2160 + 2880) = 5040
Hence, option B is correct
By: Munesh Kumari ProfileResourcesReport error
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