Explanation:

It is by default assumed that All the Maths books are distinct from each other. Similar is the case for rest of the books.

We Can make 4 units of them like this:-

MMM HHHH CCC BB
-------  --------  -----  -----

And these 4 units can be arranged in 4! ways. 

Further They are arranged themselves in 3!, 4!, 3! and 2! ways respectively.

So the required no. of arrangements = 4! × 3! × 4! × 3! ×2! = 41472