Two pipes A and B can fill a tank in 36 min and 45 min respectively A waste pipe C can empty the tan...........

Quantitative Aptitude ( CCS) Pipes&cistern

Two pipes A and B can fill a tank in 36 min. and 45 min. respectively. A waste pipe C can empty the tank in 30 min. First A and B are opened. After 7 min., C is also opened. In how much time, the tank is full ?

60 min

46 min

39 min

13 min

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Explanation:

.

(A + B)'s 7 minutes filling =(5+4)×7=63(5+4)×7=63 units

Remaining capacity =180−63=117180−63=117 units

Now C is opened, it empties by 6 units/min.

So total units filled in tank is =(5+4)−6=3(5+4)−6=3 units/min

Now tank can be filled in

=1173=391173=39min

Tank is filled up in

= 7+39 minutes=467+39 minutes=46 min