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Divide 56 into two parts such that three times the first part exceeds one third of the second by 48. The parts are :
20, 36
25, 31
24, 32
None of these
Let the first part be x and the other part is (56 - x) Three times the first part exceeds one third of the second party by 48 3x = 1/3(56-x) + 48 9x = 56-x + 144 9x + x = 200 10x = 200 x = 20 First part = 20 Second part = 36
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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