I 6x2 ndash 23 radic 3x 60 0 II 2y2 3 radic 3y ndash 15 0 ........

Quantitative Aptitude ( CCS) Quadratic Equations

Directions: In each question two equations numbered I and II are given. You have to solve both the equations and mark the answer

I. 6x² – 23√3x + 60 = 0

II. 2y² + 3 √3y – 15 = 0

if x > y

if x ≥ y

if x < y

if x ≤ y

if x = y or the relation between x and y can't be determined

I. 6x2 – 23√3x + 60 = 0

6x2 – 8√3x – 15√3x + 60 = 0

2x(3x – 4√3) – 5√3 (3x – 4√3) = 0

(2x – 5√3)(3x – 4√3) = 0

x = 2.5√3,1.33√3

II. 2y2 + 3√3y – 15 = 0

2y2 + 5√3y – 2√3y – 15 = 0

y (2y + 5√3) – √3 (2y + 5√3) = 0

(2y + 5√3)(y – √3) = 0

y = √3,– 2.5√3

Therefore, for any value of x and any value of y

x > y

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