I 4x2 ndash 8 radic 10 x 2 radic 10 0 II 2y2 ndash 4 3 radic 11 y 6 radic 1...........

Quantitative Aptitude ( CCS) Quadratic Equations

Directions: In each question two equations numbered I and II are given. You have to solve both the equations and mark the answer

I. 4x2 – (8 + √10)x + 2√10 = 0

II. 2y2 – (4 + 3√11)y + 6√11 = 0

if x > y

if x ≥ y

if x < y

if x ≤ y

if x = y or the relation between x and y can't be determined

I. 4x2 – (8 + √10)x + 2√10 = 0

4x2 – 8x – √10x + 2√10 = 0

4x(x – 2) – √10 (x – 2) = 0

(4x – √10) (x – 2) = 0

x=2, √10/4

II. 2y2 – (4 + 3√11)y + 6√11 = 0

= 2y2 – 4y –3√11y + 6√11 = 0

= 2y(y – 2) – 3√11(y – 2) = 0

= (2y – 3√11) (y – 2) = 0

y=2,3 √11/2

While comparing the root the root values of x and y, we find that the root values of y is greater than equal to x.

Hence, the option D is correct.

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