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Question 1:
8% of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner by obtaining 48% of the total votes, defeated his contestant by 1100 votes. The total number of voters in the election was:
A). 21000 B). 23500 C). 22000 D). 27500
Solution:
Let total votes = x
Votes polled=x×92/100
Votes polled for winner=48/100 × x= 48x/100
Votes polled for loser=(92x/100−48x/100)
According to the question,
48x/100−42x/100=1100
4x=1100×100
x=1100×25=27500
Question 2:
In an election between two candidates, 75% of the voters cast their votes, out of which 2% votes were declared invalid. A candidate got 9261 votes which were 75% of the valid votes. The total number of voters enrolled in that election was:
A). 16000 B). 16400 C). 16800 D). 18000
let total voter be 100% of x now vote polled = 75% of x now 2% voters are declared invalid => valid voters = 98% of ( 75% of x ) Winner candidate got 75% of total valid votes i.e 75% of { 98% of (75% of x )} = 9261
=> x = 16800
Question 3:
In an assembly election, a candidate got 55% of the total valid votes. 2% of the total votes were declared invalid. If the total number of voters is 104000, then the number of valid votes polled in favour of the candidate is :
A). 56506 B). 56650 C). 56560 D). 56056
Total votes = 104000
Total valid votes
=104000×98/100
=101920
Votes polled in favour of the candidate
=101920×55/100
=56056
Question 4:
In an election, there are three candidates contested. The first candidates got 40% votes and the second got 36% votes. If total number of votes polled were 36000, find the number of votes got by the 3rd candidate.
A). 8040 B). 8640 C). 9360 D). 9640
Let the total number of votes = 100 units According to the question, 100 units = 36000 1 unit = 360 24 units =360×24=8640
Question 5. A salesman is allowed 12% commission on the total sales made by him and a bonus of 1% on the sales over Rs 15000. If the total earning of the sales man is 7650 Rs. Find the total sales? A) 60,000 B) 50,000 C) 80,000 D) 90,000
Sale upto 15000 rs 12% of 15000 = 1800 remaining amount = { 7650-1800 } = 5850 now 1% after 15000 12%+1% = 13% = 5850 1% = 5850/13 = 450 100% = 45000 ( sale after 15000 ) i.e total sale = 15000 + 45000 = 60000 option A
Question 6: A salesman gets commission on total sales at 9%. If the sale is exceeded Rs.10,000 he gets an additional commission as bonus of 3% on the excess of sales over Rs.10,000. If he gets total commission of Rs.1380, then the bonus he received is:
Commission up to 10000 = 10000 x 9/100 =10000x9/100 = 900
Again after 10000,
Commission : Bonus
9 : 3
3x : x
Therefore, Bonus = (1380−900)×1/4 = Rs. 120
OR
sale upto Rs. 10000 , 9% commission i.e 9% of 10000 = 900 rs left amount ( 1380 - 900 ) = 480 now if sale over Rs.10000 : 9% + 3% = 12 % = 480 1% = 40 3% = 120
Ratios and Fractions based question
Question 7: If the numerator of a fraction is increased by 20% and the denominator is decreased by 5%, the value of the new fraction become 5/2. The original fraction is: A) 24/19 B) 3/18 C) 95/48 D) 48/95
Solution: Let original fraction be p/y According to the question, {(120/100)p/(95/100)y} = 5/2 120p/95y = 5/2 => p/y = (5/2)x (95/120) = 95/48.
Question 8:The monthly income of a person was Rs 13500 and his monthly expenditure was Rs 9000. Next year his income increased by 14% and his expenditure increased by 7%. The per cent increase inhis savings was: A) 7% B) 21% C) 28% D) 35%
Solution: Given, monthly income = 13500 and expenditure = 9000 Then, original savings= Rs. (13500-9000) = Rs 4500 New income = 114% of Rs. 13500 = Rs 15390 New expenditure= 107% of Rs 9000 = Rs 9630 New saving = Rs. (15390 – 9630) = Rs 5760 NS = new savings OS = Original savings Percentage increase in savings = {(NS – OS)/OS} X 100 {(5760 – 4500)/4500} X 100 = (1260/4500)X 100 = 28%
OR income = exp + savings 13500 = 9000 + 4500 reduce the equation by diciding by 4500 on both sides i.e 3 = 2 + 1 now multiply by 100 both sides 300 = 200 + 100 now 14% of 300 = 42 7% of 200 = 14 now we need to increase savings ( because 342 = 214 + k ) k = savings k = 342- 214 = 128 now savings is 100 and finally the savings is 128 28 % incriment .
Let Vipul's salary = Rs.x
5% of x = 5x/100 =x/20 As given, 1687.50 = 75/100 * x/20 = 3x/80 =>3x=1687.50 * 80 =>x= 1687.50*80/3
Question 10: A vessel has 60 L of solution of acid and water having 80% acid. How much water is to be added to make it solution in which acid forms 60%? A) 48 L B) 20 L C) 36 L D) None of these
Solution: Given, percentage of acid = 80% Then, percentage of water = 20% In 60L of solution, water = (60 x 20)/ 100 = 12L and remaining is acid = 48 lt. Now in the new solution percentage of acid is 60 % 100 %
acid 60% + water 40 % if we add water then acid in the mixture be constant i.e if acid is constant then - 60% of this final mixture be = 48 1% = 8 lt 100% = 80 lt. => 80-60 = 20 lt .
option b
By: Munesh Kumari ProfileResourcesReport error
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