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Of all the important topics in the quantitative aptitude section for various Government exams, the simplification and approximation questions are one of the most frequently asked questions.
Aspirants who are preparing for the upcoming Government exams must know that the simplification/ approximation questions are the one where marks can be scored easily without ant errors if solved carefully and efficiently.
The weightage of questions asked from this topic mostly varies between 3-5 questions and this topic is generally included in the initial phases of the examination.
In this article, we shall discuss in detail the concept of approximation and simplification and how to solve questions based on this topic. For the reference of candidates, we have also given some sample questions to make the topic more understandable.
Explanation: Whenever we find ‘of’ in a simplification problem, we can replace that by ‘multiplication(*)’. Similarly ‘/’ can be replaced by ‘÷’.
Example: Find ¼ of 20
Solution: (¼) x 20 = 20÷4 = 5
Rule-(II) Always keep in mind the “BODMAS” rule. These operations have priorities in the same order as mentioned.
Explanation: Whenever we have more than one operation in the given calculation, we have to do the operations according to the priority specified by ‘BODMAS’
Example: Simplify: (2+3)*30
Solution: In this question, we have two things-Bracket & Multiplication. According to the BODMAS rule, we have to solve bracket first and not multiplication. So now coming to bracket, we have only one operation-Addition, so we will do addition.
(2+3)*30 = 5*30
Now we have only one operation to do – Multiplication
5*30 = 150
Example: Simplify: (2+5) of 80
Solution: In this question, we have three things – bracket, addition & of. Replacing ‘of’ by ‘multiplication’.
(2+5) of 30 = (2+5)*80
Now we have three things – bracket, addition & Multiplication. According to the BODMAS rule, we have to solve bracket first and not multiplication. So now coming to bracket, we have only one operation-Addition, we will do addition.
(2+5)*80 = 7*80
Now we will do multiplication.
7*80 = 560
Rule-(III) Multiplication & Division have the same priority(Do that operation first which is on left)
Explanation: Though division has more priority than multiplication according to ‘BODMAS’ but we can perform any of the two operations first if mutiplication is on left.
Example: 8*30/15
8*30 ÷ 15
Solution: In this question, we have two things – Multiplication & Division. Multiplication is on left So we can perform that first.
Doing Multiplication first:
240 ÷ 15
16
Doing division first:
8*2
Rule-(IV) Addition & Subtraction have the same priority.
Explanation: Though addition has more priority than division according to ‘BODMAS’ but we can perform any of the two operations first.
Example: 30+40-15
Solution: In this question, we have two things – Addition & Subtraction. So we can perform any operation first as they have same priority.
Doing Addition first:
70 – 15
55
Doing Subtraction first:
30 + 25
Rule-(V) Don’t hesitate in rounding the numbers to nearest integers.
Explanation: Most of the times the numbers are given in such a way that you can round them quickly and get the answer (Rounding should be done or not, It can be realised by looking at the given options).
Example: (324.5*15)/(5.01*24.98)
Solution: (325*15)/(5*25)
=13*3
=39
Now let us see some of the previous year questions asked from 'Simplification' & try to apply the rules learnt so far.
Q. 1) (17 -13)4 - 174 – 134 – [- 52(17)3 – 68(133)] = (?)*221
1) 1432
2) 1326
3) 1450
4) 1567
5) 1234
Using formula: (a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3+ b4) ⇒ (a – b)4 - a4 + 4a3b + 4ab3 - b4 = + 6a2b2 (17 -13)4 - 174 – 134 – [- 52(17)3 – 68(133)] = (?)*221 Here, a = 17 and b = 13 ⇒ (?)= (6 (17)2 (13)2)/221 ⇒ (?) = (6 × 289 × 169)/221 ⇒ (?) = 1326
Option 2 is correct
Q.2) Simplify: 127.001 * 7.998 + 6.05 * 4.001
Solution: Using the rounding concept
127 * 8 + 6 * 4
Using the BODMAS rule
1016 + 24
1040 (Option 3)
Q.3) What will come at place of ?: 9876 ÷ 24.96 + 215.005 - ? = 309.99
9875 ÷ 25 + 215 - ? = 310
395 + 215 - ? = 310
610 - ? = 310
? = 300 (Option 4)
Q.4) What will come at place of a: (128 ÷ 16 x a – 7*2)/(72-8*6+a2) = 1
Solution: Using the BODMAS rule
(8*a – 14)/(49-48+a2) = 1
(8*a – 14)/(1 + a2) = 1
8a – 14 = 1 + a2
a2 – 8a + 15 = 0
a=3 or 5 (Option 2)
Q.5) What will come at place of ?:
85.147 + 34.192*6.2 + ? = 802.293
85 + 35*6 + ? = 803
85 + 210 + ? = 803
295 + ? = 803
? = 508 [approx. = 500] (Option 5)
Q.6) What will come at place of ? : (3/8 of 168)*15 ÷ 5 + ? = 549 ÷ 9 + 235
(3*168÷8)*15 ÷ 5 + ? = 549 ÷ 9 + 235
(504÷8)*3 + ? = 61 + 235
63*3 + ? = 296
189 + ? = 296
? = 107 (Option 2)
By: Munesh Kumari ProfileResourcesReport error
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