Bhuvan and Kachara started doing the work After working for 5 Days they left the work...........

Quantitative Aptitude ( CCS) Time and work

Direction: Study the following Table and answer the questions that follow:

Bhuvan and Kachara started doing the work. After working for 5 Days they left the work for Tipu. He completed his part of work. Now the remaining work was completed by Arjan in 7.5 days. In how many days can Arjan complete whole work?

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Explanation:

Explanation – Bhuvan: 15% = 6 days
100% = (6/15) × 100
= 40 days
Kachara: 15% = 3 days
100% = (3/15) × 100
= 20 days
Tipu: 25% = 4 days
100% = 16 days
Now we can find the Total work by taking LCM of number of days taken by Bhuvan, Kachara and Tipu
LCM ( 40 , 20, 16) = 80 unit (Total work)
Now we can find efficiency of each persons.
Bhuvan = 2 unit
Kachra = 4 unit
In 1 days Bhuvan and Kachara complete 6 unit of work
so in 5 day = 6 × 5 = 30 unit
Tipu completes 25% of total work = 80 × 25/100 = 20 unit
Remaining work = 80 – (30+20)
= 30 unit
Arjan completes it in 7.5 days,
Efficiency of Arjan = 30 /7.5 = 4 unit ( in 1 day)
Arjan can complete total work in,
= 80/4
= 20 days