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If the angles of elevation of a tower from two points distance a and b (a > b) from its foot and in the same straight line from it are 30° and 60°, then the height of the tower is?
√a + b
√a - b
Let AB be the tower and P and Q are such points that PB = a,
QB = b and angles of elevation at P and Q are 30° and 60° respectively
By: Amit Kumar ProfileResourcesReport error
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