The angles of depression of two ships from the top of a light house are 45 deg and 30 deg towards ea...........

Quantitative Aptitude ( CCS) Height and Distance

The angles of depression of two ships from the top of a light house are 45° and 30° towards east. If the ships are 100 m apart, the height of the light house is

50 /√3 + 1 m

50 /√3 - 1 m

50(√3 - 1) m

50(√3 + 1) m

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Explanation:

Let AB be the light house C and D are two ships whose angles of depression on A are 30° and 45° respectively

∠ACB = ∠XAC = 30° , ∠ADB = ∠YAD = 45° and
CD = 100m
Let AB =h and CB = x then BC = (100 - x)m
Now in ΔACB,