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From a lighthouse the angles of depression of two ships on opposite sides of the light house are observed to be 30° and 45°. If the height of the lighthouse is h metres, the distance between the ships is
(√3 + 1)h meters
(√3 - 1)h meters
1 + (1 + 1/√3)h meters
Let AB be lighthouse and P and Q are two ships on its opposite sides which form angle of elevation of A as 45° and 30° respectively AB = h
Let PB = x and QB = y
By: Amit Kumar ProfileResourcesReport error
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