The probability that in the random arrangement of the letters of the word CAPSLOCK the two C 39 s do...........

Quantitative Aptitude (CDS) Probability

The probability that in the random arrangement of the letters of the word CAPSLOCK ,the two C's does not come together is?

3/4

5/4

7/4

2/7

The total number of arrangements of the letters of the word CAPSLOCK is =8!/2!

The number of arrangements when both C's are together=7!

So the number of arrangements in which both C's do not come together =8!/2! -7!

Therefore the required probability=(8!/2! -7!)/(8!/2!)

=(8! -7!×2!)/8!

=7!(8-2)/8!

=6/8

=3/4

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