If P X 6 13 and P Y 5 11 and P X Y 7 8 then find P X Y ........

Quantitative Aptitude (CDS) Probability

If P(X)=6/13 and P(Y)=5/11 and P(X?Y)=7/8, then find P(X?Y).

47/1001

21/1005

27/1195

44/1805

Given P(X)=6/13 ,P(Y)=5/11,P(X?Y)=7/8

As we know that

P(X?Y)=P(X)+P(Y)-P(X?Y)

Thus P(X?Y)=P(X)+P(Y)-P(X?Y)

=6/13+5/11-7/8

=(528+520-1001)/1144

=47/1001

Submit Error