send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Please specify
Please verify your mobile number
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Find the equation of the line passing through (2, -1) and perpendicular to the line 2x – y = 4.
x+2y=0
Y=5x-2
Y=2x-5
None of these
Slope of the given line is 2. By comparing with y=mx+c The perpendicular lines have the product of their slopes= (-1) So, slope of new line will be (-1/2) Equation of line will be y=mx+c M=-1/2 So we get, y= (-1/2)x+k We are given the point (2,-1) that will satisfy this line. Putting these coordinates we get k=0 and the line becomes = x+2y=0
By: Amit Kumar ProfileResourcesReport error
Access to prime resources