send mail to firstname.lastname@example.org mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
Please verify your mobile number
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Refer & Earn
My Abhipedia Earning
Kindly Login to view your earning
Find the equation of straight line passing through (2, 3) and perpendicular to the line 3x + 2y + 4 = 0
y =5/3x- 2
None of these
The given line is 3x + 2y + 4 = 0 or y = (-3x/2) - 2
Any line perpendicular to it will have slope = 2/3
Thus equation of line through (2, 3) and slope 2/3 is
(y – 3) = 2/3 (x – 2)
⇒ 3y – 9 = 2x – 4
⇒ 3y – 2x – 5 = 0.
⇒ 3y = 2x + 5
By: Amit Kumar ProfileResourcesReport error
Access to prime resources