send mail to firstname.lastname@example.org mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
Please verify your mobile number
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Refer & Earn
My Abhipedia Earning
Kindly Login to view your earning
What is the area enclosed in the region defined by y = |x – 1| + 2, line x = 1, X–axis and Y–axis?
5 sq units
2.5 sq units
10 sq units
7 sq units
The required area is essentially the area of the shaded region.
The point of intersection of y = |x – 1| + 2 where the y–axis can be found by substituting x = 0 in the equation.
Thus we get y = 3.
Required area = Area of the trapezium formed by the points (0, 0), (1, 0), (1, 2) and (0, 3).
Area of a trapezium = 1/2 * height * sum of the parallel sides
= 1/2 * 1 * (3 + 2) = 5/2 sq units
= 2.5 sq units
By: Amit Kumar ProfileResourcesReport error
Access to prime resources