send mail to email@example.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
Please verify your mobile number
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Refer & Earn
My Abhipedia Earning
Kindly Login to view your earning
What is the equation of a set of points equidistant from the lines y = 5 and x = –4?
x + y = –1
x – y = –1
x + y = 1
–x + y = –1
A set of points equidistant from the given two lines should lie on the dotted line as indicated. You can think of it as the perpendicular bisector to the base of an isosceles triangle formed by (–4, 5) and the two points on x = –4 and y = 5.
Or, the set of points equidistant from two lines form the angle bisector of the angle formed at the point of intersection of the two lines. The angle between these two lines is 900. Importantly, the lines are parallel to the axes. So, thinking of the line that is the angle bisector of this angle should not be too difficult.
This dotted line is at an angle of 135o with respect to the positive direction of x–axis and also passes through (–4, 5).
Slope = m = tan (135o) = –1.
Therefore, the equation is given by (y – y1) = m
(x – x1) where (x1, y1) is (–4, 5).
(y – 5) = –(x + 4)
x + y = 1
By: Amit Kumar ProfileResourcesReport error
Access to prime resources