Two coins were tossed at a time what is the probability of getting at most one head ........

Quantitative Aptitude (CDS) Probability

. Two coins were tossed at a time, what is the probability of getting at most one head?

5/4

7/4

3/2

3/4

Possible outcomes were

(H,H) ,(H,T) ,(T,H) ,(T,T)

Let A be the event of getting one head.

A={ (H,T),(T,H) }

Let B be the event of getting no head.

B={ (T,T) }

Total number of outcomes =4

Therefore P(A)=2/4=1/2

and P(B)=¼

Thus required probability=P(A ) +P(B)

=½+¼

=3/4

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