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A team has three engineers A, B, and C. The software crashes if all the three engineers failed to resolve the problem. The probabilities of not resolving the problem are 0.3,0.06 and 0.24 for engineers A, B, and C respectively. What is the probability that the software will not crash?
0.992
0.99994
0.99568
0.0043
Since probabilities of failure for engineers A, B, and C i.e P(A), P(B), and P(C) are 0.3,0.06 and 0.24 respectively.
The software will crash only when all three engineers failed to resolve the problem.
So, the probability that it crashes =P(A).P(B).P(C)
=0.3×0.06×0.24
=0.00432
Hence the probability that the software will not crash=1-0.00432
=0.99568
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