A team has three engineers A B and C The software crashes if all the three engineers failed to resol...........

Explanation:

Since probabilities of failure for engineers A, B, and C i.e P(A), P(B), and P(C) are 0.3,0.06 and 0.24 respectively.

The software will crash only when all three engineers failed to resolve the problem.

So, the probability that it crashes =P(A).P(B).P(C)

=0.3×0.06×0.24

=0.00432

Hence the probability that the software will not crash=1-0.00432

=0.99568