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A, B and C participated in a burger eating competition. A beat C by 18 burgers. A also beat B by eating 50% more burger than B. Also B had eaten 5 percentage points more burger than C. Find the overall number of burgers that were eaten.
Let the burgers eaten by C be x%
=> Burgers eaten by B = x + 5%
Since A ate 50% more than B = (x + 5%) + 50% of (x+5%) = 1.5 (x+5%)
=> x + x + 5 + 1.5(x+ 5) = 100%
=> x = 87.5/3.5 = 25
Therefore, A beat C by 20 percentage points => 18 => Total burger = 18 * 100/20 = 90
The overall number of burgers that were eaten is 90.
By: Amit Kumar ProfileResourcesReport error
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