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In a local election, 2400 people were to vote for Party A or Party B. Party A was bound to win the election. However, on Election Day, one-third of the voters of Party A were kidnapped. Party B was also able to influence the remaining Party A voters and thus double the strength of its voters. In this way, Party A lost by a majority which was half of that by which it would have won had the elections been fair. How many people finally voted for Party A and Party B?
If 600 voted for A and 1200 voted for B then
Before influencing, A = 600 + 600 = 1200, B = 1200 – 600 = 600
(As half of B’s vote were through influencing)
Before kidnapping, A = 1200 + a∗12 of 1200 = 1800
(As 1/3 of A’s voters were kidnapped which is half of the 2/3 that remained)
Thus, total voter initially = 1800 (A) + 600 (B) = 2400
600 would have voted for Party A, 1200 would have voted for Party B.
Hence, the answer is 600(A), 1200(B)
By: Amit Kumar ProfileResourcesReport error
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