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A two digit number ab is 60% of x. The two-digit number formed by reversing the digits of ab is 60% more than x. Find x.
45
54
63
72
10a + b = 0.6x 10b + a = 1.6x Subtracting one from the other, we have 9b - 9a = x or x = 9 (b - a) x should be a multiple of 9. 10a + b = 3x/5 this implies that x should also be a multiple of 5. Or, x should be a multiple of 45 x should be equal to 45, ab = 27, ba = 72 x should be equal to 45
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