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Tom, Jerry and Bill start from point A at the same time in their cars to go to B. Tom reaches point B first and turns back and meets Jerry at a distance of 9 miles from B. When Jerry reaches B, he too turns back and meets Bill at a distance of 7 miles from B. If 3 times the speed with which Tom drives his car is equal to 5 times Bill’s speed, what could be the distance between the points A and B?
40 miles
24 miles
31 miles
63 miles
Let the distance between A and B be ‘x’ miles. Let their speeds be T, J and B in miles/hour When Tom meets Jerry: Distance travelled by Tom = x + 9 Distance travelled by Jerry = x – 9 Time taken will be the same => x + 9 /T = x + 9 /J or T/J = x + 9 /x - 9 ...........(i) When Jerry meets Bill: Distance travelled by Jerry = x + 7 Distance travelled by Bill = x – 7 Time taken will be the same => x + 7 /J = x - 7 /B 5(x - 9)(x - 7) = 3 (x + 9)(x + 7) 5x2 – 80x + 315 = 3x2 + 48x + 189 2x2 – 128x + 126 = 0 x2 – 64x + 63 = 0 x = 63 or x = 1 Therefore, X has to be 63 miles
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