A train of length 150 m takes 10 sec to pass another train 100 m long coming from opposite direction...........

Quantitative Aptitude ( CCS) Time & distance

A train of length 150 m takes 10 sec to pass another train 100 m long coming from opposite direction. If the speed of the first train is 30 km/hr, the speed of the second train is

54 km/hr

60 km/hr

72 km/hr

36 km/hr

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Explanation:

Let speed of the other train = S m /sec.
Speed of the first train = 30 kmph = (30 *5)/18 = 8.33 m/sec.
Relative speed = (8.33 + S) m/sec.
With this relative speed train needs to be covered (150 + 100) m in 10 seconds.
So,
ST = D
(8.33 + S) * 10 = 250
(8.33 + S) = 25
S = 16.67 m/sec
Speed = 16.67 m/sec = (16.67 * 18)/5 = 60 kmph