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A fruit seller has oranges, apples and guavas in the ratio 2:5:8. The number of apples is more than the number of oranges by a number that is a multiple of both 6 and 8. What is the minimum number of fruits in his shop?
240
360
120
90
Let the number of fruits be 2k, 5k and 8k Given, 5k – 2k = multiple of 6 and 8 LCM of 6 and 8 is 24 Let’s say 5k – 2k = 24n 3k = 24n For k to be a natural number and have minimum value, n should be equal to 1 3k = 24 Or k = 8 Hence, the number of fruits = 2k + 5k + 8k = 15 * 8= 120
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