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N is an 80-digit positive integer (in the decimal scale). All digits except the 44th digit (from the left) are 2. If N is divisible by 13, find the 44th digit?
5
6
1
2
Any number of the form abcabc is a multiple of 1001. 1001 is 7 * 11 * 13. So, any number of the form abcabc is a multiple of 13. 42 digits ......... 43 44 .... remaining 36 digits 222222 ..... 222222 2 a 222222............222222 Or we can write this 80 digit number as, 222222 ......2222220000000 ............000000 (It has 42 2's and 38 0's and it is divisible by 13) + 00000 .......00000 2 a 000000............000000 (43rd digit is 2 and 44th digit is a) + 00000 ..........000000 222222.............222222 (It has 36 2's in the end and it is divisible by 13) We are left with a two digit number 2a. 26 is a multiple of 13, so the 44th digit should be 6.
By: Amit Kumar ProfileResourcesReport error
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