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[x] is the greatest integer less than or equal to x. Find the number of positive integers n such that [n/11] = [n/13].
31
25
35
40
This is a classic case of brute-force counting. When n = 1, 2, 3....10, both values will be equal to 0. 10 possibilities When n = 13, 14, ....21, both values will be equal to 1. 9 possibilities When n = 26, 27, ....32, both values will be equal to 2. 7 possibilities When n = 39, 27, ....43, both values will be equal to 3. 5 possibilities When n = 52, 53, 54, both values will be equal to 4. 3 possibilities when n = 65, both will be equal to 5. 1 possibility So, totally there are 1 + 3 + 5 + 7 + 9 + 10 = 35 possibilities.
By: Amit Kumar ProfileResourcesReport error
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