send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
Three numbers leave remainders of 43, 47 and 49 on division by N. The sum of the three numbers leaves a remainder 9 on division by N. What are the values N can take?
65
96
125
More than one value is possible
the sum of the three numbers should leave a remainder 43 + 47 + 49 = 139. Or, it should be of the form N * k + 139, where K is an integer. However, it leaves a remainder 9, or it is of the form N * m + 9. N * k + 139 = N * m + 9 N * (m - k) = 130 Or, N should be a factor of 130. Since the remainders left on division by N are 43, 47 and 49, N should be greater than 49. The only factors of 130 that are greater than 49 are 65 and 130. So, N can take 2 values – 65 or 130.
By: Amit Kumar ProfileResourcesReport error
Access to prime resources
New Courses