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Find the smallest number that has exactly 18 factors.
180
216
240
None of these
Any number of the form paqbrc will have (a + 1) (b + 1) (c + 1) factors, where p, q, r are prime. (This is a very important idea) Now, the number we are looking for has 18 factors. It can comprise one prime, two primes or three primes. Now, 18 can be written as 1 * 18 or 3 * 6 or 9 * 2 or 2 * 3 * 3. If we take the underlying prime factorization of N to be paqb, then it can be of the form p1q8 or p2q5 If we take the underlying prime factorization of N to be pa, then it can be of the form p17 If we take the underlying prime factorization of N to be paqbrc, then it can be of the form p1q2r2 So, N can be of the form p17, p2q5, p1q8 or p1q2r2 Importantly, these are the only possible prime factorizations that can result in a number having 18 factors. Now, let us think of the smallest possible number in each scenario p17 - Smallest number = 217 p2q5 – 32 * 25 p1q8 – 31 * 28 p1q2r2 – 51 * 32 * 22 The smallest of these numbers is 51 * 32 * 22 = 180
By: Amit Kumar ProfileResourcesReport error
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