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How many pairs of positive integers x, y exist such that HCF (x, y) + LCM (x, y) = 91?
10
8
6
7
Let us x = h * a; y = h * b a and b are co-prime. So, LCM of (x, y) = h * a * b So, in essence h + h * a * b = 91. Or h(ab + 1) = 91 Now, 91 can be written as 1 * 91 or 7 * 13 Or, we can have HCF as 1, LCM as 90 - There are 4 pairs of numbers like this (2, 45), (9, 10), (1, 90) and (5, 18) We can have HCF as 7, ab + 1 = 13 => ab = 12 => 1 * 12 or 4 * 3 Or, the pairs of numbers are (7, 84) or (21, 28) The third option is when HCF = 13, ab + 1 = 7 => ab = 6 Or (a, b) can be either (1, 6) or (2, 3) The pairs possible are (13, 78) and (26, 39) There are totally 8 options possible - (2, 45), (9, 10), (1, 90), (5, 18), (7, 84), (21, 28), (13, 78) and (26, 39). 8 Pairs.
By: Amit Kumar ProfileResourcesReport error
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