Let the least number of six digits be N which when divided by 4 6 10 and 15 leaves in each cas...........

Quantitative Aptitude ( CCS) Number System

Let the least number of six digits be 'N', which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2. Find the sum of the digits in N?

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Explanation:

Least number of 6 digits is 100000.
L.C.M. of 4, 6, 10 and 15 = 60.
On dividing 100000 by 60, the remainder obtained is 40.
∴ Least number of 6 digits divisible by 4, 6, 10 and 15 = 100000 + (60 - 40) = 100020.
∴ N = (100020 + 2) = 100022. Sum of digits in N = (1 + 2 + 2) = 5.